Some accepted solutions fail on certain edge cases because they don’t properly handle arrays where all elements are the same or where negative numbers are included. These cases are not covered in the ...

If an out-of-bounds exception is thrown, then the two text cases from hitting run pass. int current = 1; for(int i = 1; i <= nums.length; i++){ if(!(nums[i] == nums ...

push() and pop(), these two methods append elements to an array and remove an element from the an array respectively. Both of these methods work at the end of the array, where the index is largest.

Abstract: Detecting duplicates over sliding windows is an important technique for monitoring and analysing data streams. Since recording the exact information of elements in a sliding window can be ...